A blind man is handed a deck of 52 cards and told that exactly 10 of these cards are facing up. How can he divide the cards into two piles, not necessarily of equal size, with each pile having the same number of cards facing up?
Subscribe to:
Post Comments (Atom)
Solution :
ReplyDeleteDivide cards into 2 groups one having 10 cards (group I) and other having 42 cards (group II).
Now in group-I suppose 7 cards are facing up,since there were 10 facing up earlier , so 3 cards will be facing up in group-II.
Now flip all the cards in group-I , so we will have 3 facing up .
Done...
nee mokam.. eppudu chusina.. oka chinna example teeskoni.. solution cheptav.. adedo aa example ki pani chestunate.. eppudaina generic ga rayi ra
ReplyDelete@Raghu sir
ReplyDeleteGeneric solution for you.
If the original pile has 'C' cards with 'U' cards facing up.
Then divide them into 2 groups of U and C-U.
Flip all the U cards to get equal no. of cards
facing up in both the groups.